c. Each AMP will 80 tasks in parallel
So,
1. PE sessions, handled in parallel would be = 120 sessions * 16 requests = 1920
2. Tasks handled by each amp = 80 in parallel, So No.of Amps required to handle 1920 requests would be,
1920 / 80 tasks = 24 AMPs (Does this mean that we require minimum 24 AMPs to handle 1920 requests for the above mentioned limitation)
Just wanted to understand, how much the default system can handle the requests simulatenously....
We say that the limitations of :
a. one PE can handle 120 sessions in parallel (http://www.info.teradata.com/HTMLPubs/DB_TTU_14_00/Utilities/B035_1102_111A/Gtwglobal.36.001.html)
b. Each session can run 16 requests in parallel
(http://www.terateamuk.com/teradata_glossary_of_terms/teradata_terms_a-d/teradata_Amp_Worker_tasks.html)
(http://my.safaribooksonline.com/book/databases/9781940540184/chapter-3-amp-worker-tasks/sub4_chapter03_xhtm)
c. Each AMP will 80 tasks in parallel
So,
1. PE sessions, handled in parallel would be = 120 sessions * 16 requests = 1920
2. Tasks handled by each amp = 80 in parallel, So No.of Amps required to handle 1920 requests would be,
1920 / 80 tasks = 24 AMPs (Does this mean that we require minimum 24 AMPs to handle 1920 requests for the above mentioned limitation)
Is this correct ?